# PROGRAM TO FIND ANSWER OF THE FOLLOWING SERIES. SUM=X-X3/3!+X5/5!-X7/7!+...

```#include<stdio.h>
#include<conio.h>
void main()
{
long int x,i,j,k,n,sq,cnt;
double fact,sum=0;
clrscr();
printf(\"\\n ENTER THE VALUE OF N: \");
scanf(\"%ld\",&n);
printf(\"\\n ENTER THE VALUE OF X: \");
scanf(\"%ld\",&x);
for(i=1,cnt=1;i<=n;i=i+2,cnt++)
{
for(j=1,sq=1;j<=i;j++)
sq=sq*x;
printf(\"\\n SQ = %ld\",sq);
for(k=1,fact=1;k<=i;k++)
fact=fact*k;
printf(\"\\n fact = %7.2lf\",fact);

if(cnt%2==1)
sum=sum+(sq/fact);
else
sum=sum-(sq/fact);
printf(\"\\n THE SUM OF THIS SERIES IS %7.2lf\\n\",sum);
}
getch();

}

****************************** OUTPUT *********************************

ENTER THE VALUE OF N: 5

ENTER THE VALUE OF X: 2

SQ = 2
fact =    1.00
THE SUM OF THIS SERIES IS    2.00

SQ = 8
fact =    6.00
THE SUM OF THIS SERIES IS    0.67

SQ = 32
fact =  120.00
THE SUM OF THIS SERIES IS    0.93

**************************************************************************
```

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