Program to find number of days b/w two given dates

 #include<iostream.h>
 #include<conio.h>



 //------------------------------  day  ----------------------------------//


 class day
    {
       private:
        int date;
        int month;
        int year;

       public:
        day()  {  date=0; month=0; year=0;  }
        void get_date();
        void show_days(day,day);
        void show_date();
        int next_month(int,int);
        int next_year(int);
        int operator>(day);
    };


 //---------------------------  get_date( )  -----------------------------//


 void day::get_date()
    {
       cout<<\"\\tEnter the date = \";
       cin>>date;

       cout<<\"\\tEnter the month = \";
       cin>>month;

       cout<<\"\\tEnter the year = \";
       cin>>year;
    }


 //--------------------------  show_date( )  -----------------------------//


 void day::show_date()
    {
       cout<<\"\\n\\t Date is     \";
       cout<<((date<10)?\"0\":\"\")<<this->date<<\" : \";
       cout<<((month<10)?\"0\":\"\")<<this->month<<\" : \"<<this->year<<endl;
    }


 //---------------------------  show_days(day,day)  ----------------------//


 void day::show_days(day d1,day d2)
    {
    long d=0;

    if(d2.date<d1.date && d2.month!=d1.month && d2.year>=d1.year)
       {
          d2.date+=next_month(d2.month-1,d2.year);
          d2.month--;
       }

    for(int count_1=d1.date;count_1<d2.date;count_1++)
       d++;

    if(d2.month<d1.month && d2.year>d1.year)
       {
          d2.month+=12;
          d2.year--;
       }

    for(int count_2=d1.month;count_2<d2.month;count_2++)
       d+=next_month(count_2,d1.year);

    for(int count_3=d1.year;count_3<d2.year;count_3++)
       d+=365+next_year(count_3);

    cout<<\"\\t Number of days b/w date1 & date2 = \"<<d<<\" days\"<<endl;
    }


 //---------------------------  operator>(day)  --------------------------//


 int day::operator>(day d)
    {
       long d1;
       long d2;

       d2=date+(month*30)+(year*360);
       d1=d.date+(d.month*30)+(d.year*360);
       return (d2>d1?1:0);
    }


 //-------------------------  next_month(int,int)  -----------------------//


 int day::next_month(int m,int y)
    {
       int d;

       if(m<1)
      m+=12;

       else if(m>12)
      m-=12;

       switch(m)
      {
         case 1 : d=31;
              break;

         case 2 : d=28+next_year(y);
              break;

         case 3 : d=31;
              break;

         case 4 : d=30;
              break;

         case 5 : d=31;
              break;

         case 6 : d=30;
              break;

         case 7 : d=31;
              break;

         case 8 : d=31;
              break;

         case 9 : d=30;
              break;

         case 10 : d=31;
              break;

         case 11 : d=30;
              break;

         case 12 : d=31;
              break;
      }

       return d;
    }


 //---------------------------  next_year(int)  --------------------------//


 int day::next_year(int y)
    {
       if(y%4==0 || y%4==0 || y%100==0)
      return 1;

       else
      return 0;
    }



 //-----------------------------  Main( )  -------------------------------//



 main()
    {
       clrscr();

       day date_1;
       day date_2;
       day date_3;

       cout<<\"\\n Enter the date in the pattern i.e  dd/mm/yy \"<<endl;

       cout<<\"\\n  First Date :\"<<endl;
       date_1.get_date();

       cout<<\"\\n  Second Date :\"<<endl;
       date_2.get_date();

       cout<<\"\\n********** First Date **********\"<<endl;
       date_1.show_date();

       cout<<\"\\n********** Second Date **********\"<<endl;
       date_2.show_date();

       cout<<\"\\n********** Result **********\\n\"<<endl;
       if(date_1>date_2)
      date_3.show_days(date_2,date_1);

       else
      date_3.show_days(date_1,date_2);

       getch();
       return 0;
    }